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# JEE Advanced 2016 Paper 1 Mathematics Question 40

A computer producing factory has only two plants $T_1$ and $T_2$. Plant $T_1$ produces 20% and plant $T_2$ produces 80% of the total computers produced. 7% of computers produced in the factory turn out to be defective. It is known that

P(computer turns out to be defective given that it is produced in the plant $T_1$) = 10P(computer turns out to be defective given that it is produced in the plant $T_2$)

where P(E) denotes the probability of an event E. A computer produced in the factory is randomly selected and it does not turn out to be defective. Then the probability that it is produced in plant $T_2$ is

## Trueshelf Team

### Dr. Shiva Kintali

Dr. Shiva Kintali is the Founder & CEO of TrueShelf. Before that, he started a Machine Learning startup that was successfully acquired. Before that, he was teaching in the Computer Science department of Princeton University for four years. He has over 17 years of (academic and industry, theoretical and practical) experience in algorithm design, complexity theory, machine learning, algorithmic game theory, natural language processing, information retrieval, high-performance computing and large-scale graph algorithms.